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4.6x^2=54-2x
We move all terms to the left:
4.6x^2-(54-2x)=0
We add all the numbers together, and all the variables
4.6x^2-(-2x+54)=0
We get rid of parentheses
4.6x^2+2x-54=0
a = 4.6; b = 2; c = -54;
Δ = b2-4ac
Δ = 22-4·4.6·(-54)
Δ = 997.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{997.6}}{2*4.6}=\frac{-2-\sqrt{997.6}}{9.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{997.6}}{2*4.6}=\frac{-2+\sqrt{997.6}}{9.2} $
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